How can I add a help method to a shell script?
here's an example for bash:
usage="$(basename "$0") [-h] [-s n] -- program to calculate the answer to life, the universe and everything
where:
-h show this help text
-s set the seed value (default: 42)"
seed=42
while getopts ':hs:' option; do
case "$option" in
h) echo "$usage"
exit
;;
s) seed=$OPTARG
;;
:) printf "missing argument for -%s\n" "$OPTARG" >&2
echo "$usage" >&2
exit 1
;;
\?) printf "illegal option: -%s\n" "$OPTARG" >&2
echo "$usage" >&2
exit 1
;;
esac
done
shift $((OPTIND - 1))
To use this inside a function:
- use
"$FUNCNAME"
instead of$(basename "$0")
- add
local OPTIND OPTARG
before callinggetopts
The first argument to a shell script is available as the variable $1
, so the simplest implementation would be
if [ "$1" == "-h" ]; then
echo "Usage: `basename $0` [somestuff]"
exit 0
fi
But what anubhava said.
here is a part I use it to start a VNC server
#!/bin/bash
start() {
echo "Starting vnc server with $resolution on Display $display"
#your execute command here mine is below
#vncserver :$display -geometry $resolution
}
stop() {
echo "Killing vncserver on display $display"
#vncserver -kill :$display
}
#########################
# The command line help #
#########################
display_help() {
echo "Usage: $0 [option...] {start|stop|restart}" >&2
echo
echo " -r, --resolution run with the given resolution WxH"
echo " -d, --display Set on which display to host on "
echo
# echo some stuff here for the -a or --add-options
exit 1
}
################################
# Check if parameters options #
# are given on the commandline #
################################
while :
do
case "$1" in
-r | --resolution)
if [ $# -ne 0 ]; then
resolution="$2" # You may want to check validity of $2
fi
shift 2
;;
-h | --help)
display_help # Call your function
exit 0
;;
-d | --display)
display="$2"
shift 2
;;
-a | --add-options)
# do something here call function
# and write it in your help function display_help()
shift 2
;;
--) # End of all options
shift
break
;;
-*)
echo "Error: Unknown option: $1" >&2
## or call function display_help
exit 1
;;
*) # No more options
break
;;
esac
done
######################
# Check if parameter #
# is set too execute #
######################
case "$1" in
start)
start # calling function start()
;;
stop)
stop # calling function stop()
;;
restart)
stop # calling function stop()
start # calling function start()
;;
*)
# echo "Usage: $0 {start|stop|restart}" >&2
display_help
exit 1
;;
esac
It's a bit weird that I placed the start stop restart in a separate case but it should work
For a quick single option solution, use if
If you only have a single option to check and it will always be the first option ($1
) then the simplest solution is an if
with a test ([
). For example:
if [ "$1" == "-h" ] ; then
echo "Usage: `basename $0` [-h]"
exit 0
fi
Note that for posix compatibility =
will work as well as ==
.
Why quote $1
?
The reason the $1
needs to be enclosed in quotes is that if there is no $1
then the shell will try to run if [ == "-h" ]
and fail because ==
has only been given a single argument when it was expecting two:
$ [ == "-h" ]
bash: [: ==: unary operator expected
For anything more complex use getopt
or getopts
As suggested by others, if you have more than a single simple option, or need your option to accept an argument, then you should definitely go for the extra complexity of using getopts
.
As a quick reference, I like The 60 second getopts tutorial.†
You may also want to consider the getopt
program instead of the built in shell getopts
. It allows the use of long options, and options after non option arguments (e.g. foo a b c --verbose
rather than just foo -v a b c
). This Stackoverflow answer explains how to use GNU getopt
.
† jeffbyrnes mentioned that the original link died but thankfully the way back machine had archived it.
Better to use getopt facility of bash. Please look at this Q&A for more help: Using getopts in bash shell script to get long and short command line options