how to map more than one property from array of object in javascript
I have an array of Object as follows:
var obj = [
{a: 1, b: 5, c: 9},
{a: 2, b: 6, c: 10},
{a: 3, b: 7, c: 11},
{a: 4, b: 8, c: 12}
];
I know about how to get single object using Array.map()
like this.
var result = obj.map(x=>x.a)
This will give me following result
[1, 2, 3, 4]
But I want result like follows:
[
{a: 1, b: 5},
{a: 2, b: 6},
{a: 3, b: 7},
{a: 4, b: 8}
]
inshort from array of object i want to select only few fields(more than one)
how to do that ?
You can use .map()
with Object Destructuring:
let data = [
{a:1,b:5,c:9}, {a:2,b:6,c:10},
{a:3,b:7,c:11}, {a:4,b:8,c:12}
];
let result = data.map(({ a, b }) => ({a, b}));
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
If, as in your example, you want to exclude a particular property or few, you can use destructuring and use rest properties to create an object with only the properties you want:
var obj = [
{a:1,b:5,c:9},
{a:2,b:6,c:10},
{a:3,b:7,c:11},
{a:4,b:8,c:12}
];
const mapped = obj.map(({ c, ...rest }) => rest);
console.log(mapped);
If you want to include properties, simply extract them from the .map
callback:
var obj = [
{a:1,b:5,c:9},
{a:2,b:6,c:10},
{a:3,b:7,c:11},
{a:4,b:8,c:12}
];
const mapped = obj.map(({ a, b }) => ({ a, b }));
console.log(mapped);
Use map()
:
var data = [
{a:1,b:5,c:9},
{a:2,b:6,c:10},
{a:3,b:7,c:11},
{a:4,b:8,c:12}
];
let modified = data.map(obj => ({a: obj.a, b: obj.b}))
console.log(modified);
Or if you prefer destructuring:
var data = [
{a:1,b:5,c:9},
{a:2,b:6,c:10},
{a:3,b:7,c:11},
{a:4,b:8,c:12}
];
let modified = data.map(({ a, b }) => ({a, b}));
console.log(modified);
var obj = [
{a: 1, b: 5, c: 9},
{a: 2, b: 6, c: 10},
{a: 3, b: 7, c: 11},
{a: 4, b: 8, c: 12}
];
var result = obj.map(e => ({a:e.a , b:e.b}));
console.log(result)
You can return a custom object with required properties using map()
var obj = [{a:1,b:5,c:9},
{a:2,b:6,c:10},
{a:3,b:7,c:11},
{a:4,b:8,c:12}
];
let op = obj.map(e => {
return { a:e.a, b: e.b };
})
console.log(op);