How to know function return type and argument types?

Solution 1:

Well things have changed a little bit since 2011! Now there's type hints in Python 3.5 which you can use to annotate arguments and return the type of your function. For example this:

def greeting(name):
  return 'Hello, {}'.format(name)

can now be written as this:

def greeting(name: str) -> str:
  return 'Hello, {}'.format(name)

As you can now see types, there's some sort of optional static type checking which will help you and your type checker to investigate your code.

for more explanation I suggest to take a look at the blog post on type hints in PyCharm blog.

Solution 2:

This is how dynamic languages work. It is not always a good thing though, especially if the documentation is poor - anyone tried to use a poorly documented python framework? Sometimes you have to revert to reading the source.

Here are some strategies to avoid problems with duck typing:

  • create a language for your problem domain
  • this will help you to name stuff properly
  • use types to represent concepts in your domain language
  • name function parameters using the domain language vocabulary

Also, one of the most important points:

  • keep data as local as possible!

There should only be a few well-defined and documented types being passed around. Anything else should be obvious by looking at the code: Don't have weird parameter types coming from far away that you can't figure out by looking in the vicinity of the code...

Related, (and also related to docstrings), there is a technique in python called doctests. Use that to document how your methods are expected to be used - and have nice unit test coverage at the same time!

Solution 3:

I attended a coursera course, there was lesson in which, we were taught about design recipe.

Below docstring format I found preety useful.

def area(base, height):
    '''(number, number ) -> number    #**TypeContract**
    Return the area of a tring with dimensions base   #**Description**
    and height

    >>>area(10,5)          #**Example **
    25.0
    >>area(2.5,3)
    3.75
    '''
    return (base * height) /2 

I think if docstrings are written in this way, it might help a lot to developers.

Link to video [Do watch the video] : https://www.youtube.com/watch?v=QAPg6Vb_LgI

Solution 4:

Actually there is no need as python is a dynamic language, BUT if you want to specify a return value then do this

def foo(a) -> int: #after arrow type the return type 
       return 1 + a

In the example above it will return int if you will give a string perimeter such as "hello" to it then it will throw this exception TypeError: unsupported operand type(s) for +: 'int' and 'str' because it has asked for a int value and we gave it a string value and lastly because we can't add int and string

and then for argument type do this

def foo(a: int) -> int:
      return a+ 1

after the colon (:)you can specify the argument type