Open Run... dialog from command
I would like to run the Run... dialog (the Win+R) from a batch command? There is an shotcut to it in C:\Users\USER\AppData\Roaming\Microsoft\Windows\Start Menu\Programs\System Tools
but that shotcut goes nowhere, the target is just "Run..." and the target directory is my desktop.
How can I run the dialog from a command?
Solution 1:
Vista or later
If you are on Windows Vista or later, it will come with PowerShell. The PowerShell one-liner (New-Object -ComObject "Shell.Application").FileRun()
will work.
You can run this directly from the legacy command line (or within a batch file) with the following:
powershell -c (New-Object -ComObject "Shell.Application").FileRun()
This is an adaptation of the VBScript command outlined below.
Pre-Vista
For older versions of Windows (this will also work in newer versions, but requires an additional file), you can do this via VBScript, using the Shell object:
dim oShell = CreateObject("shell.application")
oShell.FileRun()
Shrinking it into one line:
CreateObject("shell.application").FileRun()
Simple put that line into its own plain text file and save it with the extension .vbs
, e.g. ShowRunDialog.vbs
. Then run ShowRunDialog.vbs
from the command line.
This indirectly runs the RunFileDlg
function contained within shell32.dll
. See here.
Solution 2:
This command can be launched from any program/script to show "Run" dialog:
explorer.exe Shell:::{2559a1f3-21d7-11d4-bdaf-00c04f60b9f0}