How to round each item in a list of floats to 2 decimal places?
I have a list which consists of float values but they're too detailed to proceed. I know we can shorten them by using the ("%.f" % variable)
operator, like:
result = [359.70000000000005]
result = "%.2f" % result
result = [359.70]
My question is how can I turn a list of values into their rounded equivalents without using an iterator. I've tried something, but it throws a TypeError
:
list = [0.30000000000000004, 0.5, 0.20000000000000001]
list = "%.2f" % list
TypeError: not all arguments converted during string formatting
How can I provide a clean list like:
list = [0.30, 0.5, 0.20]
"%.2f"
does not return a clean float. It returns a string representing this float with two decimals.
my_list = [0.30000000000000004, 0.5, 0.20000000000000001]
my_formatted_list = [ '%.2f' % elem for elem in my_list ]
returns:
['0.30', '0.50', '0.20']
Also, don't call your variable list
. This is a reserved word for list creation. Use some other name, for example my_list
.
If you want to obtain [0.30, 0.5, 0.20]
(or at least the floats that are the closest possible), you can try this:
my_rounded_list = [ round(elem, 2) for elem in my_list ]
returns:
[0.29999999999999999, 0.5, 0.20000000000000001]
If you really want an iterator-free solution, you can use numpy and its array round function.
import numpy as np
myList = list(np.around(np.array(myList),2))