"Set Difference" between two vectors with duplicate values

I have 3 vectors

x <- c(1,3,5,7,3,8)
y <- c(3,5,7)
z <- c(3,3,8)

I want to find the elements of x that are not in y and not in z. Is there a function f that would give me the following output:

> f(x,y)
1 3 8
> f(x,z)
1 5 7

In other words, I want to find the "set difference" between 2 vectors, either of which may have repeated values. The functions %in%, match and setdiff do not work in this case for obvious reasons.

Solution 1:

There should be some better ways to do this but here is one option

get_diff_vectors <- function(x, y) {
  count_x <- table(x)
  count_y <- table(y)
  same_counts <- match(names(count_y), names(count_x))
  count_x[same_counts] <- count_x[same_counts] - count_y
  as.numeric(rep(names(count_x), count_x))
}

get_diff_vectors(x, y)
#[1] 1 3 8
get_diff_vectors(x, z)
#[1] 1 5 7
get_diff_vectors(x, c(5, 7))
#[1] 1 3 3 8

We count the frequency of x and y using table, match the numbers which occur in both and subtract the counts y from x. Finally recreate the remaining vector using rep.

Still not able to find a better way but here is dplyr way using the somewhat similar logic.

library(dplyr)

get_diff_vectors_dplyr <- function(x, y) {
  df1 <- data.frame(x) %>% count(x)
  df2 <- data.frame(y) %>% count(y)
  final <- left_join(df1, df2, by = c("x" = "y")) %>%
           mutate_at(c("n.x", "n.y"), funs(replace(., is.na(.), 0))) %>%
           mutate(n = n.x - n.y)

  rep(final$x, final$n)
}

get_diff_vectors_dplyr(x, y)
#[1] 1 3 8
get_diff_vectors_dplyr(x, z)
#[1] 1 5 7
get_diff_vectors_dplyr(x, c(5, 7))
#[1] 1 3 3 8

The vecsets package mentioned by OP has function vsetdiff which does this very easily

vecsets::vsetdiff(x, y)
#[1] 1 3 8
vecsets::vsetdiff(x, z)
#[1] 1 5 7
vecsets::vsetdiff(x, c(5, 7))
#[1] 1 3 3 8

Solution 2:

Here's an attempt using make.unique to account for duplicates:

dupdiff <- function(x,y) x[-match(
  make.unique(as.character(y)),
  make.unique(as.character(x)),
  nomatch=0
)]

Testing:

dupdiff(x,y)
#[1] 1 3 8
dupdiff(x,z)
#[1] 1 5 7
dupdiff(x, c(5, 7))
#[1] 1 3 3 8
dupdiff(x, c(5, 7, 9))
#[1] 1 3 3 8