A CSS selector to get last visible div

A tricky CSS selector question, don't know if it's even possible.

Lets say this is the HTML layout:

<div></div>
<div></div>  
<div></div>  
<div style="display:none"></div>
<div style="display:none"></div>  

I want to select the last div, which is displayed (ie. not display:none) which would be the third div in the given example. Mind you, the number of divs on the real page can differ (even the display:none ones).

You could select and style this with JavaScript or jQuery, but CSS alone can't do this.

For example, if you have jQuery implemented on the site, you could just do:

var last_visible_element = $('div:visible:last');

Although hopefully you'll have a class/ID wrapped around the divs you're selecting, in which case your code would look like:

var last_visible_element = $('#some-wrapper div:visible:last');

The real answer to this question is, you can't do it. Alternatives to CSS-only answers are not correct answers to this question, but if JS solutions are acceptable to you, then you should pick one of the JS or jQuery answers here. However, as I said above, the true, correct answer is that you cannot do this in CSS reliably unless you're willing to accept the :not operator with the [style*=display:none] and other such negated selectors, which only works on inline styles, and is an overall poor solution.

Try

div:not([style*="display: none"]):last-child

If you can use inline styles, then you can do it purely with CSS.

I am using this for doing CSS on the next element when the previous one is visible:

div[style='display: block;'] + table {
  filter: blur(3px);
}