Getting Raw XML From SOAPMessage in Java
I've set up a SOAP WebServiceProvider in JAX-WS, but I'm having trouble figuring out how to get the raw XML from a SOAPMessage (or any Node) object. Here's a sample of the code I've got right now, and where I'm trying to grab the XML:
@WebServiceProvider(wsdlLocation="SoapService.wsdl")
@ServiceMode(value=Service.Mode.MESSAGE)
public class SoapProvider implements Provider<SOAPMessage>
{
public SOAPMessage invoke(SOAPMessage msg)
{
// How do I get the raw XML here?
}
}
Is there a simple way to get the XML of the original request? If there's a way to get the raw XML by setting up a different type of Provider (such as Source), I'd be willing to do that, too.
Solution 1:
You could try in this way.
SOAPMessage msg = messageContext.getMessage();
ByteArrayOutputStream out = new ByteArrayOutputStream();
msg.writeTo(out);
String strMsg = new String(out.toByteArray());
Solution 2:
If you have a SOAPMessage
or SOAPMessageContext
, you can use a Transformer
, by converting it to a Source
via DOMSource
:
final SOAPMessage message = messageContext.getMessage();
final StringWriter sw = new StringWriter();
try {
TransformerFactory.newInstance().newTransformer().transform(
new DOMSource(message.getSOAPPart()),
new StreamResult(sw));
} catch (TransformerException e) {
throw new RuntimeException(e);
}
// Now you have the XML as a String:
System.out.println(sw.toString());
This will take the encoding into account, so your "special characters" won't get mangled.
Solution 3:
It turns out that one can get the raw XML by using Provider<Source>, in this way:
import java.io.ByteArrayOutputStream;
import javax.xml.transform.Source;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.stream.StreamResult;
import javax.xml.ws.Provider;
import javax.xml.ws.Service;
import javax.xml.ws.ServiceMode;
import javax.xml.ws.WebServiceProvider;
@ServiceMode(value=Service.Mode.PAYLOAD)
@WebServiceProvider()
public class SoapProvider implements Provider<Source>
{
public Source invoke(Source msg)
{
StreamResult sr = new StreamResult();
ByteArrayOutputStream out = new ByteArrayOutputStream();
sr.setOutputStream(out);
try {
Transformer trans = TransformerFactory.newInstance().newTransformer();
trans.transform(msg, sr);
// Use out to your heart's desire.
}
catch (TransformerException e) {
e.printStackTrace();
}
return msg;
}
}
I've ended up not needing this solution, so I haven't actually tried this code myself - it might need some tweaking to get right. But I know this is the right path to go down to get the raw XML from a web service.
(I'm not sure how to make this work if you absolutely must have a SOAPMessage object, but then again, if you're going to be handling the raw XML anyways, why would you use a higher-level object?)