How to convert String to Int in Kotlin?
I am working on a console application in Kotlin where I accept multiple arguments in main()
function
fun main(args: Array<String>) {
// validation & String to Integer conversion
}
I want to check whether the String
is a valid integer and convert the same or else I have to throw some exception.
How can I resolve this?
Solution 1:
You could call toInt()
on your String
instances:
fun main(args: Array<String>) {
for (str in args) {
try {
val parsedInt = str.toInt()
println("The parsed int is $parsedInt")
} catch (nfe: NumberFormatException) {
// not a valid int
}
}
}
Or toIntOrNull()
as an alternative:
for (str in args) {
val parsedInt = str.toIntOrNull()
if (parsedInt != null) {
println("The parsed int is $parsedInt")
} else {
// not a valid int
}
}
If you don't care about the invalid values, then you could combine toIntOrNull()
with the safe call operator and a scope function, for example:
for (str in args) {
str.toIntOrNull()?.let {
println("The parsed int is $it")
}
}
Solution 2:
Actually, there are several ways:
Given:
var numberString : String = "numberString"
// number is the int value of numberString (if any)
var defaultValue : Int = defaultValue
Then we have:
Operation | Numeric value | Non-numeric value |
---|---|---|
numberString.toInt() | number | NumberFormatException |
numberString.toIntOrNull() | number | null |
numberString.toIntOrNull() ?: defaultValue | number | defaultValue |
If numberString
is a valid integer, we get number
, else see a result in column Non-numeric value
.
Solution 3:
val i = "42".toIntOrNull()
Keep in mind that the result is nullable as the name suggests.
Solution 4:
As suggested above, use toIntOrNull()
.
Parses the string as an [Int] number and returns the result or
null
if the string is not a valid representation of a number.
val a = "11".toIntOrNull() // 11
val b = "-11".toIntOrNull() // -11
val c = "11.7".toIntOrNull() // null
val d = "11.0".toIntOrNull() // null
val e = "abc".toIntOrNull() // null
val f = null?.toIntOrNull() // null