Convert char to int in C and C++
Solution 1:
Depends on what you want to do:
to read the value as an ascii code, you can write
char a = 'a';
int ia = (int)a;
/* note that the int cast is not necessary -- int ia = a would suffice */
to convert the character '0' -> 0
, '1' -> 1
, etc, you can write
char a = '4';
int ia = a - '0';
/* check here if ia is bounded by 0 and 9 */
Explanation:a - '0'
is equivalent to ((int)a) - ((int)'0')
, which means the ascii values of the characters are subtracted from each other. Since 0
comes directly before 1
in the ascii table (and so on until 9
), the difference between the two gives the number that the character a
represents.
Solution 2:
Well, in ASCII code, the numbers (digits) start from 48. All you need to do is:
int x = (int)character - 48;
Or, since the character '0' has the ASCII code of 48, you can just write:
int x = character - '0'; // The (int) cast is not necessary.