Only extracting text from this element, not its children

Solution 1:

what about .find(text=True)?

>>> BeautifulSoup.BeautifulSOAP('<html>yes<b>no</b></html>').find(text=True)
u'yes'
>>> BeautifulSoup.BeautifulSOAP('<html><b>no</b>yes</html>').find(text=True)
u'no'

EDIT:

I think that I've understood what you want now. Try this:

>>> BeautifulSoup.BeautifulSOAP('<html><b>no</b>yes</html>').html.find(text=True, recursive=False)
u'yes'
>>> BeautifulSoup.BeautifulSOAP('<html>yes<b>no</b></html>').html.find(text=True, recursive=False)
u'yes'

Solution 2:

You could use contents

>>> print soup.html.contents[0]
yes

or to get all the texts under html, use findAll(text=True, recursive=False)

>>> soup = BeautifulSoup.BeautifulSOAP('<html>x<b>no</b>yes</html>')
>>> soup.html.findAll(text=True, recursive=False) 
[u'x', u'yes']

above joined to form a single string

>>> ''.join(soup.html.findAll(text=True, recursive=False)) 
u'xyes'

Only extracting text from this element, not its children

Solution 1:

Solution 2:

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