How to redirect output with subprocess in Python?

What I do in the command line:

cat file1 file2 file3 > myfile

What I want to do with python:

import subprocess, shlex
my_cmd = 'cat file1 file2 file3 > myfile'
args = shlex.split(my_cmd)
subprocess.call(args) # spits the output in the window i call my python program

In Python 3.5+ to redirect the output, just pass an open file handle for the stdout argument to subprocess.run:

# Use a list of args instead of a string
input_files = ['file1', 'file2', 'file3']
my_cmd = ['cat'] + input_files
with open('myfile', "w") as outfile:
    subprocess.run(my_cmd, stdout=outfile)

As others have pointed out, the use of an external command like cat for this purpose is completely extraneous.

UPDATE: os.system is discouraged, albeit still available in Python 3.

Use os.system:

os.system(my_cmd)

If you really want to use subprocess, here's the solution (mostly lifted from the documentation for subprocess):

p = subprocess.Popen(my_cmd, shell=True)
os.waitpid(p.pid, 0)

OTOH, you can avoid system calls entirely:

import shutil

with open('myfile', 'w') as outfile:
    for infile in ('file1', 'file2', 'file3'):
        shutil.copyfileobj(open(infile), outfile)

@PoltoS I want to join some files and then process the resulting file. I thought using cat was the easiest alternative. Is there a better/pythonic way to do it?

Of course:

with open('myfile', 'w') as outfile:
    for infilename in ['file1', 'file2', 'file3']:
        with open(infilename) as infile:
            outfile.write(infile.read())

One interesting case would be to update a file by appending similar file to it. Then one would not have to create a new file in the process. It is particularly useful in the case where a large file need to be appended. Here is one possibility using teminal command line directly from python.

import subprocess32 as sub

with open("A.csv","a") as f:
    f.flush()
    sub.Popen(["cat","temp.csv"],stdout=f)

How to redirect output with subprocess in Python?

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