Unmarshal 2 different structs in a slice
My input json data is this (cannot be changed, from an external resource):
[{
"Url": "test.url",
"Name": "testname"
},{
"FormName": "Test - 2018",
"FormNumber": 43,
"FormSlug": "test-2018"
}]
I have two structs that will always match the data within the array:
type UrlData struct{
"Url" string `json:Url`
"Name" string `json:Name`
}
type FormData struct{
"FormName" string `json:FormName`
"FormNumber" string `json:FormNumber`
"FormSlug" string `json:FormSlug`
}
Obviously the code below will not work, but is it possible at the top level (or otherwise) to declare something like this:
type ParallelData [
urlData UrlData
formData FormData
]
Solution 1:
Use a two step process for unmarshaling. First, unmarshal a list of arbitrary JSON, then unmarshal the first and second element of that list into their respective types.
You can implement that logic in a method called UnmarshalJSON, thus implementing the json.Unmarshaler interface. This will give you the compound type you are looking for:
type ParallelData struct {
UrlData UrlData
FormData FormData
}
// UnmarshalJSON implements json.Unmarshaler.
func (p *ParallelData) UnmarshalJSON(b []byte) error {
var records []json.RawMessage
if err := json.Unmarshal(b, &records); err != nil {
return err
}
if len(records) < 2 {
return errors.New("short JSON array")
}
if err := json.Unmarshal(records[0], &p.UrlData); err != nil {
return err
}
if err := json.Unmarshal(records[1], &p.FormData); err != nil {
return err
}
return nil
}
Try it on the playground: https://play.golang.org/p/QMn_rbJj-P-
Solution 2:
I think Answer of Peter is awesome.
Option 1:
type ParallelData [
urlData UrlData
formData FormData
]
if you need above structure then you can define it as
type UrlData struct {
Url string `json:"Url,omitempty"`
Name string `json:"Name,omitempty"`
}
type FormData struct {
FormName string `json:"FormName,omitempty"`
FormNumber string `json:"FormNumber,omitempty"`
FormSlug string `json:"FormSlug,omitempty"`
}
type ParallelData struct {
UrlData UrlData `json:"UrlData,omitempty"`
FormData FormData `json:"FormData,omitempty"`
}
In this case, your json will look like
[
{
"UrlData":{
"Url":"test.url",
"Name":"testname"
}
},
{
"FormData":{
"FormName":"Test - 2018",
"FormNumber":"43",
"FormSlug":"test-2018"
}
}
]
Option 2:
You've provide following json:
[
{
"Url":"test.url",
"Name":"testname"
},
{
"FormName":"Test - 2018",
"FormNumber":43,
"FormSlug":"test-2018"
}
]
If your json really look like, then you can use following struct
type UrlData struct {
Url string `json:Url`
Name string `json:Name`
}
type FormData struct {
FormName string `json:FormName`
FormNumber int `json:FormNumber`
FormSlug string `json:FormSlug`
}
type ParallelData struct {
UrlData
FormData
}
For both options, you can Unmarshall your json like this
var parallelData []ParallelData
err := json.Unmarshal([]byte(str), ¶llelData)
if err != nil {
panic(err)
}
fmt.Println(parallelData)
See option 1 in playground
See option 2 in playground
Solution 3:
You can unmarshal into a map[string]interface{}
for example:
type ParallelData map[string]interface{}
func main() {
textBytes := []byte(`[
{
"Url": "test.url",
"Name": "testname"
},
{
"FormName": "Test - 2018",
"FormNumber": 43,
"FormSlug": "test-2018"
}]`)
var acc []ParallelData
json.Unmarshal(textBytes, &acc)
fmt.Printf("%+v", acc)
}
Output:
=> [map[Url:test.url Name:testname] map[FormName:Test - 2018 FormNumber:43 FormSlug:test-2018]]
Playground