Convert RGB values to Integer

I think the code is something like:

int rgb = red;
rgb = (rgb << 8) + green;
rgb = (rgb << 8) + blue;

Also, I believe you can get the individual values using:

int red = (rgb >> 16) & 0xFF;
int green = (rgb >> 8) & 0xFF;
int blue = rgb & 0xFF;

int rgb = ((r&0x0ff)<<16)|((g&0x0ff)<<8)|(b&0x0ff);

If you know that your r, g, and b values are never > 255 or < 0 you don't need the &0x0ff

Additionaly

int red = (rgb>>16)&0x0ff;
int green=(rgb>>8) &0x0ff;
int blue= (rgb)    &0x0ff;

No need for multipling.

if r, g, b = 3 integer values from 0 to 255 for each color

then

rgb = 65536 * r + 256 * g + b;

the single rgb value is the composite value of r,g,b combined for a total of 16777216 possible shades.

int rgb = new Color(r, g, b).getRGB();

To get individual colour values you can use Color like following for pixel(x,y).

import java.awt.Color;
import java.awt.image.BufferedImage;

Color c = new Color(buffOriginalImage.getRGB(x,y));
int red = c.getRed();
int green = c.getGreen();
int blue = c.getBlue();

The above will give you the integer values of Red, Green and Blue in range of 0 to 255.

To set the values from RGB you can do so by:

Color myColour = new Color(red, green, blue);
int rgb = myColour.getRGB();

//Change the pixel at (x,y) ti rgb value
image.setRGB(x, y, rgb);

Please be advised that the above changes the value of a single pixel. So if you need to change the value entire image you may need to iterate over the image using two for loops.