remove url parameters with javascript or jquery
Solution 1:
What am I missing?
Why not:
url.split('?')[0]
Solution 2:
Hmm... Looking for better way... here it is
var onlyUrl = window.location.href.replace(window.location.search,'');
Solution 3:
Example: http://jsfiddle.net/SjrqF/
var url = 'youtube.com/watch?v=3sZOD3xKL0Y&feature=youtube_gdata';
url = url.slice( 0, url.indexOf('&') );
or:
Example: http://jsfiddle.net/SjrqF/1/
var url = 'youtube.com/watch?v=3sZOD3xKL0Y&feature=youtube_gdata';
url = url.split( '&' )[0];
Solution 4:
Use this function:
var getCleanUrl = function(url) {
return url.replace(/#.*$/, '').replace(/\?.*$/, '');
};
// get rid of hash and params
console.log(getCleanUrl('https://sidanmor.com/?firstname=idan&lastname=mor'));If you want all the href parts, use this:
var url = document.createElement('a');
url.href = 'https://developer.mozilla.org/en-US/search?q=URL#search-results-close-container';
console.log(url.href); // https://developer.mozilla.org/en-US/search?q=URL#search-results-close-container
console.log(url.protocol); // https:
console.log(url.host); // developer.mozilla.org
console.log(url.hostname); // developer.mozilla.org
console.log(url.port); // (blank - https assumes port 443)
console.log(url.pathname); // /en-US/search
console.log(url.search); // ?q=URL
console.log(url.hash); // #search-results-close-container
console.log(url.origin); // https://developer.mozilla.org