How to select last child element in jQuery?

How to select last child element in jQuery?

Just the last child, not its descendants.

You can also do this:

<ul id="example">
    <li>First</li>
    <li>Second</li>
    <li>Third</li>
    <li>Fourth</li>
</ul>

// possibility 1
$('#example li:last').val();
// possibility 2
$('#example').children().last()
// possibility 3
$('#example li:last-child').val();

:last

.children().last()

:last-child

For perfomance:

$('#example').children().last()

or if you want a last children with a certain class as commented above.

$('#example').children('.test').last()

or a specific child element with a specific class

$('#example').children('li.test').last()

By using the :last-child selector?

Do you have a specific scenario in mind you need assistance with?

For 2019 ...

jQuery 3.4.0 is deprecating :first, :last, :eq, :even, :odd, :lt, :gt, and :nth. When we remove Sizzle, we’ll replace it with a small wrapper around querySelectorAll, and it would be almost impossible to reimplement these selectors without a larger selector engine.

We think this trade-off is worth it. Keep in mind we will still support the positional methods, such as .first, .last, and .eq. Anything you can do with positional selectors, you can do with positional methods instead. They perform better anyway.

https://blog.jquery.com/2019/04/10/jquery-3-4-0-released/

So you should be now be using .first(), .last() instead (or no jQuery).