Constructor Chaining Order
If you chain constructor calls using the syntax:
public frmConfirm(): this(1)
when is the overloaded constructor called? Also, can somebody confirm that if the class is a form, problems will arise from having the InitializeComponent() call in both constructors?
Solution 1:
The chained constructor will be called immediately prior to the body of the defining constructor. The IL sequence generated is an immediate call
to the other constructor, followed by the IL generated from the statements in the constructor.
So if you chain to another constructor and that constructor calls InitializeComponent()
the calling constructor should not call this method.
For example, given this sample class:
class Foo {
public int A, B;
public Foo() : this(1) {
B = 2;
}
public Foo(int a) {
A = a;
}
}
This is the generated IL:
.class private auto ansi beforefieldinit Foo
extends [mscorlib]System.Object
{
.field public int32 A
.field public int32 B
// method line 1
.method public hidebysig specialname rtspecialname
instance default void '.ctor' () cil managed
{
.maxstack 8
IL_0000: ldarg.0
IL_0001: ldc.i4.1
IL_0002: call instance void class Foo::'.ctor'(int32)
IL_0007: ldarg.0
IL_0008: ldc.i4.2
IL_0009: stfld int32 Foo::B
IL_000e: ret
} // end of method Foo::.ctor
// method line 2
.method public hidebysig specialname rtspecialname
instance default void '.ctor' (int32 a) cil managed
{
.maxstack 8
IL_0000: ldarg.0
IL_0001: call instance void object::'.ctor'()
IL_0006: ldarg.0
IL_0007: ldarg.1
IL_0008: stfld int32 Foo::A
IL_000d: ret
} // end of method Foo::.ctor
} // end of class Foo
Note that the no-arg constructor calls the other constructor before assigning 2 to the B field.
Solution 2:
The this(1)
constructor is called first.
As far as your second question goes, because of the InitializeComponent
and other issues with form inheritance, I'd suggest you use composition instead of inheritance.