Why doesn't my arrow function return a value?

Solution 1:

When you use the function body version of an arrow function (with {}), there is no implied return. You have to specify it. When you use the concise body (no {}), the result of the body expression is implicitly returned by the function.

So you would write that either with an explicit return:

const f = arg => { return arg.toUpperCase(); };
// Explicit return ^^^^^^

or with a concise body:

const f = arg => arg.toUpperCase();

Examples:

const f1 = arg => { return arg.toUpperCase(); };
console.log(f1("testing"));

const f2 = arg => arg.toUpperCase();
console.log(f2("testing"));

Slightly tangential, but speaking of {}: If you want the concise arrow's body expression to be an object initializer, put it in ():

const f = arg => ({prop: arg.toUpperCase()});