Angular url plus sign converting to space
You can override default angular encoding with adding Interceptor which fixes this:
import { HttpInterceptor, HttpRequest, HttpEvent, HttpHandler, HttpParams, HttpParameterCodec } from "@angular/common/http";
import { Injectable } from "@angular/core";
import { Observable } from "rxjs";
@Injectable()
export class EncodeHttpParamsInterceptor implements HttpInterceptor {
intercept(req: HttpRequest<any>, next: HttpHandler): Observable<HttpEvent<any>> {
const params = new HttpParams({encoder: new CustomEncoder(), fromString: req.params.toString()});
return next.handle(req.clone({params}));
}
}
class CustomEncoder implements HttpParameterCodec {
encodeKey(key: string): string {
return encodeURIComponent(key);
}
encodeValue(value: string): string {
return encodeURIComponent(value);
}
decodeKey(key: string): string {
return decodeURIComponent(key);
}
decodeValue(value: string): string {
return decodeURIComponent(value);
}
}
and declare it in providers section of in app.module.ts
providers: [
{
provide: HTTP_INTERCEPTORS,
useClass: EncodeHttpParamsInterceptor,
multi: true
}
]
This ia a common problem. The +
character is used by the URL to separate two words. In order to use the +
character in the parameter values, you need to encode your parameter values before adding them as part of the URL. Javascript / TypeScript provide a encodeURI()
function for that specific purpose.
URL encoding converts characters into a format that can be transmitted over the Internet. [w3Schools Reference]
Here is how you can fix this problem:
let encodedName = encodeURI('xyz+manwal');
let encodedURI = 'http://localhost:3000/page?name='+encodedName;
//.. OR using string interpolation
let encodedURI = `http://localhost:3000/page?name=${ encodedName }`;
In the same way, you can decode the parameters using decodeURI()
method.
let decodedValue = decodeURI(encodedValue);
In Angular 5.2.7+ the "+" is replaced with space " " in a query string.
Here is the corresponding commit : fix(router): fix URL serialization
If you want to change this behaviour and replace the "+" with "%2B" you can create a custom url serializer and provide it in the AppModule providers.
import { DefaultUrlSerializer, UrlSerializer, UrlTree } from '@angular/router';
export default class CustomUrlSerializer implements UrlSerializer {
private _defaultUrlSerializer: DefaultUrlSerializer = new DefaultUrlSerializer();
parse(url: string): UrlTree {
// Encode "+" to "%2B"
url = url.replace(/\+/gi, '%2B');
// Use the default serializer.
return this._defaultUrlSerializer.parse(url);
}
serialize(tree: UrlTree): string {
return this._defaultUrlSerializer.serialize(tree).replace(/\+/gi, '%2B');
}
}
@NgModule({
imports: [
BrowserModule,
BrowserAnimationsModule,
AppRoutingModule
],
declarations: [
AppComponent
],
providers: [
{ provide: UrlSerializer, useClass: CustomUrlSerializer }
],
entryComponents: [],
bootstrap: [AppComponent]
})
export class AppModule {
}
http://localhost:3000/page?name=xyz+manwal
The URL will be converted to:
http://localhost:3000/page?name=xyz%2Bmanwal
Hope this will help.
In Angular v6.1.10, if you just need to fix the "+" sign encoding in one spot, this is what worked for me.
getPerson(data: Person) {
const httpParams = new HttpParams({
fromObject: {
id: data.id,
name: data.name,
other: "xyz+manwal"
}
});
// manually encode all "+" characters from the person details
let url = BASE_URL + "/select?" + httpParams.toString().replace(/\+/gi, '%2B');
return this.http.get(url);
}
I found if you try to replace the "+" signs when initializing the httpParams
object it doesn't work. You have to do the replacement after converting httpParams
to a string, as shown on this line:
let url = BASE_URL + "/select?" + httpParams.toString().replace(/\+/gi, '%2B');
This is a quite common problem. You can pass it normally in application/x-www-form-urlencoded request. No other request will be able to correctly parse +. They will always parse it into %20 instead of %2B.
You would need to manually manipulate the query parameter, there are 2 ways:
- Encode the parameter into base64 encoding, this way no special character can break you application, but you would need to handle it also on the receiving part (decoding).
- A simplier solutions would be, before hitting the URL, replace all + signs with %2B. This way the other side will be able to decode it normaly, without the need of a special routine.
For more info you should reffer to hthe following stack overflow questions Android: howto parse URL String with spaces to URI object? and URL encoding the space character: + or %20?