Does a List<T> guarantee that items will be returned in the order they were added?
Solution 1:
The List is index based and new items will always be added to the end of the list. You can insert items at a certain index so the next items will move one position.
So yes, you can use it safely that way...
The List(T) class is the generic equivalent of the ArrayList class. It implements the IList(T) generic interface using an array whose size is dynamically increased as required.
Elements in this collection can be accessed using an integer index. Indexes in this collection are zero-based.
The List(T) is not guaranteed to be sorted. You must sort the List(T) before performing operations (such as BinarySearch) that require the List(T) to be sorted.
A List(T) can support multiple readers concurrently, as long as the collection is not modified. Enumerating through a collection is intrinsically not a thread-safe procedure. In the rare case where an enumeration contends with one or more write accesses, the only way to ensure thread safety is to lock the collection during the entire enumeration. To allow the collection to be accessed by multiple threads for reading and writing, you must implement your own synchronization.
You can read more about it on MSDN.
Solution 2:
Yes, List<T>
guarantees both insertion order and retrieval order and this is documented on MSDN (emphasis below is mine).
Insertion
List<T>.Add
Method
Adds an object to the end of the
List<T>
.
Item parameter is:
The object to be added to the end of the
List<T>
.
List<T>.AddRange
Method
Adds the elements of the specified collection to the end of the
List<T>
.
Collection parameter is:
The collection whose elements should be added to the end of the
List<T>
.
Retrieval
List<T>.Enumerator
Structure
Initially, the enumerator is positioned before the first element in the collection. At this position,
Current
is undefined. Therefore, you must callMoveNext
to advance the enumerator to the first element of the collection before reading the value ofCurrent
.
Current
returns the same object until MoveNext
is called. MoveNext
sets Current
to the next element.
Solution 3:
Yes. But it's not part of the specification.
Ref: List Class
Solution 4:
Yes according to this MSDN Forum thread