`if key in dict` vs. `try/except` - which is more readable idiom?
I have a question about idioms and readability, and there seems to be a clash of Python philosophies for this particular case:
I want to build dictionary A from dictionary B. If a specific key does not exist in B, then do nothing and continue on.
Which way is better?
try:
A["blah"] = B["blah"]
except KeyError:
pass
or
if "blah" in B:
A["blah"] = B["blah"]
"Do and ask for forgiveness" vs. "simplicity and explicitness".
Which is better and why?
Solution 1:
Exceptions are not conditionals.
The conditional version is clearer. That's natural: this is straightforward flow control, which is what conditionals are designed for, not exceptions.
The exception version is primarily used as an optimization when doing these lookups in a loop: for some algorithms it allows eliminating tests from inner loops. It doesn't have that benefit here. It has the small advantage that it avoids having to say "blah"
twice, but if you're doing a lot of these you should probably have a helper move_key
function anyway.
In general, I'd strongly recommend sticking with the conditional version by default unless you have a specific reason not to. Conditionals are the obvious way to do this, which is usually a strong recommendation to prefer one solution over another.
Solution 2:
There is also a third way that avoids both exceptions and double-lookup, which can be important if the lookup is expensive:
value = B.get("blah", None)
if value is not None:
A["blah"] = value
In case you expect the dictionary to contain None
values, you can use some more esoteric constants like NotImplemented
, Ellipsis
or make a new one:
MyConst = object()
def update_key(A, B, key):
value = B.get(key, MyConst)
if value is not MyConst:
A[key] = value
Anyway, using update()
is the most readable option for me:
a.update((k, b[k]) for k in ("foo", "bar", "blah") if k in b)
Solution 3:
From what I understand, you want to update dict A with key,value pairs from dict B
update
is a better choice.
A.update(B)
Example:
>>> A = {'a':1, 'b': 2, 'c':3}
>>> B = {'d': 2, 'b':5, 'c': 4}
>>> A.update(B)
>>> A
{'a': 1, 'c': 4, 'b': 5, 'd': 2}
>>>