How to log python exception? [duplicate]

How can I log an exception in Python?

I've looked at some options and found out I can access the actual exception details using this code:

import sys
import traceback

try:
    1/0
except:
    exc_type, exc_value, exc_traceback = sys.exc_info()
    traceback.print_exception(exc_type, exc_value, exc_traceback)

I would like to somehow get the string print_exception() throws to stdout so that I can log it.

Take a look at logging.exception (Python Logging Module)

import logging 
def foo():
    try:
        some_code()
    except:
        logging.exception('')

This should automatically take care of getting the traceback for the current exception and logging it properly.

To answer your question, you can get the string version of print_exception() using the traceback.format_exception() function. It returns the traceback message as a list of strings rather than printing it to stdout, so you can do what you want with it. For example:

import sys
import traceback

try:
    asdf
except NameError:
    exc_type, exc_value, exc_traceback = sys.exc_info()
    lines = traceback.format_exception(exc_type, exc_value, exc_traceback)
    print ''.join('!! ' + line for line in lines)  # Log it or whatever here

This displays:

!! Traceback (most recent call last):
!!   File "<stdin>", line 2, in <module>
!! NameError: name 'asdf' is not defined

However, I'd definitely recommend using the standard Python logging module, as suggested by rlotun. It's not the easiest thing to set up, but it's very customizable.