Does .net core dependency injection support Lazy<T>

I am trying to use the generic Lazy class to instantiate a costly class with .net core dependency injection extension. I have registered the IRepo type, but I'm not sure what the registration of the Lazy class would look like or if it is even supported. As a workaround I have used this method http://mark-dot-net.blogspot.com/2009/08/lazy-loading-of-dependencies-in-unity.html

config:

public void ConfigureService(IServiceCollection services)
{
    services.AddTransient<IRepo, Repo>();
    //register lazy
}

controller:

public class ValuesController : Controller 
{
    private Lazy<IRepo> _repo;

    public ValuesController (Lazy<IRepo> repo)
    {
        _repo = repo;
    }

    [HttpGet()]
    public IActionResult Get()
    {
         //Do something cheap
         if(something)
             return Ok(something);
         else
             return Ok(repo.Value.Get());
    }
}

Solution 1:

Here's another approach which supports generic registration of Lazy<T> so that any type can be resolved lazily.

services.AddTransient(typeof(Lazy<>), typeof(Lazier<>));

internal class Lazier<T> : Lazy<T> where T : class
{
    public Lazier(IServiceProvider provider)
        : base(() => provider.GetRequiredService<T>())
    {
    }
}

Solution 2:

You only need to add a registration for a factory method that creates the Lazy<IRepo> object.

public void ConfigureService(IServiceCollection services)
{
    services.AddTransient<IRepo, Repo>();
    services.AddTransient<Lazy<IRepo>>(provider => new Lazy<IRepo>(provider.GetService<IRepo>));
}

Solution 3:

To my opinion, the code below should do the work(.net core 3.1)

services.AddTransient<IRepo, Repo>();
services.AddTransient(typeof(Lazy<>), typeof(Lazy<>));