Uniqueness of meromorphic continuation

If you have two meromorphic continuations $m_1$ and $m_2$ with pole sets (contained in) the countable sets $S_1$ and $S_2$ respectively, then $U = \mathbb{C}\setminus (S_1 \cup S_2)$ is connected, and the restrictions of $m_1$ and $m_2$ to $U$ are holomorphic continuations of $f$, hence

$$m_1\lvert_U \equiv m_2\lvert_U.$$

From that, it follows that $m_1$ and $m_2$ have identical singularities in each point of $S_1 \cup S_2$.


Consider 2 different meromorphic extensions, g, and h of your function f.

Consider the function $g-h$ on the set $C /\ (S_1 \cup S_2)$. This function is holomorphic, and is zero in a open region, and thus is zero everywhere. g-h must be a meromorphic function. The only meromorphic continuation of 0 on $C \\ (S_1 \cup S_2)$ is that with removable singularities at $S_1 \cup S_2$.