What is java interface equivalent in Ruby?
Can we expose interfaces in Ruby like we do in java and enforce the Ruby modules or classes to implement the methods defined by interface.
One way is to use inheritance and method_missing to achieve the same but is there any other more appropriate approach available ?
Solution 1:
Ruby has Interfaces just like any other language.
Note that you have to be careful not to conflate the concept of the Interface, which is an abstract specification of the responsibilities, guarantees and protocols of a unit with the concept of the interface
which is a keyword in the Java, C# and VB.NET programming languages. In Ruby, we use the former all the time, but the latter simply doesn't exist.
It is very important to distinguish the two. What's important is the Interface, not the interface
. The interface
tells you pretty much nothing useful. Nothing demonstrates this better than the marker interfaces in Java, which are interfaces that have no members at all: just take a look at java.io.Serializable
and java.lang.Cloneable
; those two interface
s mean very different things, yet they have the exact same signature.
So, if two interface
s that mean different things, have the same signature, what exactly is the interface
even guaranteeing you?
Another good example:
package java.util;
interface List<E> implements Collection<E>, Iterable<E> {
void add(int index, E element)
throws UnsupportedOperationException, ClassCastException,
NullPointerException, IllegalArgumentException,
IndexOutOfBoundsException;
}
What is the Interface of java.util.List<E>.add
?
- that the length of the collection does not decrease
- that all the items that were in the collection before are still there
- that
element
is in the collection
And which of those actually shows up in the interface
? None! There is nothing in the interface
that says that the Add
method must even add at all, it might just as well remove an element from the collection.
This is a perfectly valid implementation of that interface
:
class MyCollection<E> implements java.util.List<E> {
void add(int index, E element)
throws UnsupportedOperationException, ClassCastException,
NullPointerException, IllegalArgumentException,
IndexOutOfBoundsException {
remove(element);
}
}
Another example: where in java.util.Set<E>
does it actually say that it is, you know, a set? Nowhere! Or more precisely, in the documentation. In English.
In pretty much all cases of interfaces
, both from Java and .NET, all the relevant information is actually in the docs, not in the types. So, if the types don't tell you anything interesting anyway, why keep them at all? Why not stick just to documentation? And that's exactly what Ruby does.
Note that there are other languages in which the Interface can actually be described in a meaningful way. However, those languages typically don't call the construct which describes the Interface "interface
", they call it type
. In a dependently-typed programming language, you can, for example, express the properties that a sort
function returns a collection of the same length as the original, that every element which is in the original is also in the sorted collection and that no bigger element appears before a smaller element.
So, in short: Ruby does not have an equivalent to a Java interface
. It does, however, have an equivalent to a Java Interface, and it's exactly the same as in Java: documentation.
Also, just like in Java, Acceptance Tests can be used to specify Interfaces as well.
In particular, in Ruby, the Interface of an object is determined by what it can do, not what class
is is, or what module
it mixes in. Any object that has a <<
method can be appended to. This is very useful in unit tests, where you can simply pass in an Array
or a String
instead of a more complicated Logger
, even though Array
and Logger
do not share an explicit interface
apart from the fact that they both have a method called <<
.
Another example is StringIO
, which implements the same Interface as IO
and thus a large portion of the Interface of File
, but without sharing any common ancestor besides Object
.
Solution 2:
Ruby 3 (2021)
Ruby 3.0 introduced a type system called RBS, which supports interfaces.
interface _IntegerConvertible
def to_int: () -> Integer
end
Source: https://blog.appsignal.com/2021/01/27/rbs-the-new-ruby-3-typing-language-in-action.html
Sorbet (2020)
Stripe built a static type checker called Sorbet, which supports interfaces. See Abstract Classes and Interfaces in the sorbet docs.
RSpec (Original answer, 2012)
Try rspec's "shared examples":
https://www.relishapp.com/rspec/rspec-core/v/3-5/docs/example-groups/shared-examples
You write a spec for your interface and then put one line in each implementer's spec, eg.
it_behaves_like "my interface"
Complete example:
RSpec.shared_examples "a collection" do
describe "#size" do
it "returns number of elements" do
collection = described_class.new([7, 2, 4])
expect(collection.size).to eq(3)
end
end
end
RSpec.describe Array do
it_behaves_like "a collection"
end
RSpec.describe Set do
it_behaves_like "a collection"
end
Solution 3:
Can we expose interfaces in Ruby like we do in java and enforce the Ruby modules or classes to implement the methods defined by interface.
Ruby does not have that functionality. In principle, it does not need them as Ruby uses what is called duck typing.
There are few approaches you can take.
Write implementations that raise exceptions; if a subclass attempts to use the unimplemented method, it will fail
class CollectionInterface
def add(something)
raise 'not implemented'
end
end
Along with above, you should write testing code that enforces your contracts (what other post here incorrectly call Interface)
If you find yourself writing void methods like above all the time, then write a helper module that captures that
module Interface
def method(name)
define_method(name) { |*args|
raise "interface method #{name} not implemented"
}
end
end
class Collection
extend Interface
method :add
method :remove
end
Now, combine the above with Ruby modules and you are close to what you want...
module Interface
def method(name)
define_method(name) { |*args|
raise "interface method #{name} not implemented"
}
end
end
module Collection
extend Interface
method :add
method :remove
end
col = Collection.new # <-- fails, as it should
And then you can do
class MyCollection
include Collection
def add(thing)
puts "Adding #{thing}"
end
end
c1 = MyCollection.new
c1.add(1) # <-- output 'Adding 1'
c1.remove(1) # <-- fails with not implemented
Let me emphasise once again: this is a rudimentary, as everything in Ruby happens at runtime; there is no compile time checking. If you couple this with testing, then you should be able to pick up errors. Even further, if you take the above further, you could probably be able to write an Interface that performs checking on the class first time an object of that class is created; making your tests as simple as calling MyCollection.new
... yeah, over the top :)
Solution 4:
As everyone here said, there is no interface system for ruby. But through introspection, you can implement it yourself quite easily. Here is a simple example that can be improved in many ways to help you get started:
class Object
def interface(method_hash)
obj = new
method_hash.each do |k,v|
if !obj.respond_to?(k) || !((instance_method(k).arity+1)*-1)
raise NotImplementedError, "#{obj.class} must implement the method #{k} receiving #{v} parameters"
end
end
end
end
class Person
def work(one,two,three)
one + two + three
end
def sleep
end
interface({:work => 3, :sleep => 0})
end
Removing one of the methods declared on Person or change it number of arguments will raise a NotImplementedError
.