Filter array of objects whose any properties contains a value
Solution 1:
You could filter it and search just for one occurence of the search string.
Methods used:
Array#filter
, just for filtering an array with conditions,Object.keys
for getting all property names of the object,Array#some
for iterating the keys and exit loop if found,String#toLowerCase
for getting comparable values,String#includes
for checking two string, if one contains the other.
function filterByValue(array, string) {
return array.filter(o =>
Object.keys(o).some(k => o[k].toLowerCase().includes(string.toLowerCase())));
}
const arrayOfObject = [{ name: 'Paul', country: 'Canada', }, { name: 'Lea', country: 'Italy', }, { name: 'John', country: 'Italy' }];
console.log(filterByValue(arrayOfObject, 'lea')); // [{name: 'Lea', country: 'Italy'}]
console.log(filterByValue(arrayOfObject, 'ita')); // [{name: 'Lea', country: 'Italy'}, {name: 'John', country: 'Italy'}]
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Solution 2:
Well when we already know that its not going to be a search on an object with methods, we can do the following for saving bit on time complexity :
function filterByValue(array, value) {
return array.filter((data) => JSON.stringify(data).toLowerCase().indexOf(value.toLowerCase()) !== -1);
}
Solution 3:
Use Object.keys to loop through the properties of the object. Use reduce and filter to make the code more efficient:
const results = arrayOfObject.filter((obj)=>{
return Object.keys(obj).reduce((acc, curr)=>{
return acc || obj[curr].toLowerCase().includes(term);
}, false);
});
Where term is your search term.
Solution 4:
You can always use array.filter()
and then loop through each object and if any of the values match the value you are looking for, return that object.
const arrayOfObject = [{
name: 'Paul',
country: 'Canada',
}, {
name: 'Lea',
country: 'Italy',
}, {
name: 'John',
country: 'Italy',
}, ];
let lea = arrayOfObject.filter(function(obj){
//loop through each object
for(key in obj){
//check if object value contains value you are looking for
if(obj[key].includes('Lea')){
//add this object to the filtered array
return obj;
}
}
});
console.log(lea);