Simpler way of sorting three numbers

Is there a simpler and better way to solve this problem because

1. I used too many variables.
2. I used so many if else statements
3. I did this using the brute force method

Write a program that receives three integers as input and outputs the numbers in increasing order.
Do not use loop / array.

#include <stdio.h>
main(){
   int no1;
   int no2;
   int no3;
   int sto;
   int hi;
   int lo;

   printf("Enter No. 1: ");
   scanf("%d", &no1);
   printf("Enter No. 2: ");
   scanf("%d", &no2);         
   printf("Enter No. 3: ");
   scanf("%d", &no3);

   if (no1>no2) {   
      sto=no1;    
      lo=no2;   
   } else {
      sto=no2;  
      lo=no1;  
   } 
   if (sto>no3) { 
      hi=sto;    
      if(lo>no3){         
         sto=lo;                
         lo=no3;
      }else {
         sto=no3;      
      }         
   }else hi=no3; 

   printf("LOWEST %d\n", lo);
   printf("MIDDLE %d\n", sto);
   printf("HIGHEST %d\n", hi);  

   getch(); 
}    

if (a > c)
   swap(a, c);

if (a > b)
   swap(a, b);

//Now the smallest element is the 1st one. Just check the 2nd and 3rd

if (b > c)
   swap(b, c);

Note: Swap changes the values of two variables.

Call the three variables x, y, and z, then:

if (x > y) swap(x, y);
if (y > z) swap(y, z)
if (x > y) swap(x, y);

Writing the swap function is left as an exercise for the reader. Hint: you may have to use pointers.

#include <stdio.h>
#define min(a,b) ((a)<(b)?(a):(b))
#define max(a,b) ((a)>(b)?(a):(b))
int main(){
   int a, b, c;
   int hi;
   int lo;

   printf("Enter No. 1: ");
   scanf("%d", &a);
   printf("Enter No. 2: ");
   scanf("%d", &b);         
   printf("Enter No. 3: ");
   scanf("%d", &c);

   lo = min(min(a, b), c);
   hi = max(max(a, b), c);
   printf("LOWEST %d\n", lo);
   printf("MIDDLE %d\n", a+b+c-lo-hi);
   printf("HIGHEST %d\n", hi);  

   getchar(); 
}