Find the area of the CEN triangular region
Set: $x=BM$, $y=MC$, $s=S_{CNE}$ (in m$^2$). We have: $$ x:y=5:(4+s),\quad (x+y):y=s:4. $$ Combine these to get $5:(4+s)=(s-4):4$.
Set: $x=BM$, $y=MC$, $s=S_{CNE}$ (in m$^2$). We have: $$ x:y=5:(4+s),\quad (x+y):y=s:4. $$ Combine these to get $5:(4+s)=(s-4):4$.