Finding the area of ​the region bounded by the curve $y = x^2 - 1$ and the $x$-axis, from $x = 1$ to $x= -1$ [closed]

The area of ​​the region bounded by the curve $y = x^2 - 1$ and the $x$-axis, from $x = 1$ to $x= -1$, is ...

I'm having problems with this. I dont know what I'm supposed to do with the x-axis

$Y = x^2 - 1$ is the function.

Limits to find area is from -1 to 1 using integration.

$\int_{-1}^{1}\left(x^{2}-1\right) d x$

\begin{aligned} \left[\frac{x^{3}}{3}-1 x\right]_{-1}^{1} &=\text { Upper limit }-\text { lower limit } \\ &=\left(\frac{1}{3}-1\right)-\left(\frac{-1}{3}+1\right) \\ &=-\frac{2}{3}-\left(+\frac{2}{3}\right) \\ &=-\frac{4}{3} \end{aligned}

https://revisionmaths.com/advanced-level-maths-revision/pure-maths/calculus/area-under-curve . To know how it works.