Solving a weird System of equations
Solution 1:
Hints :
If we solve for $y$, the first equation gives $$y = \frac{3x-x^3}{1-3x^2}$$
Does this ring a bell? Recall trig formulae and use the periodicity to conclude.
Hints :
If we solve for $y$, the first equation gives $$y = \frac{3x-x^3}{1-3x^2}$$
Does this ring a bell? Recall trig formulae and use the periodicity to conclude.