Get current route without parameters

To get current route without query parameters, you can use below mentioned single line:

this.router.url.split('?')[0] 

parseTree from Router helps fetching the segments without any knowledge about url structure.

import { Router } from '@angular/router';
...
constructor(private router: Router) {}
...
const urlTree = this.router.parseUrl(url);
const urlWithoutParams = urlTree.root.children['primary'].segments.map(it => it.path).join('/');

Start from here. If you have secondary outlets adjust as required.

For me, this is the cleanest solution I managed to do. I hope it helps

import { Router } from '@angular/router';
    
constructor(private router: Router){}

getUrlWithoutParams(){
   let urlTree = this.router.parseUrl(this.router.url);
   urlTree.queryParams = {}; 
   urlTree.fragment = null; // optional
   return urlTree.toString();
}