How to copy worksheet from one workbook to another one using openpyxl?

I have a large amount of EXCEL files (i.e. 200) I would like to copy one specific worksheet from one workbook to another one. I have done some investigations and I couldn't find a way of doing it with Openpyxl

This is the code I have developed so far

def copy_sheet_to_different_EXCEL(path_EXCEL_read,Sheet_name_to_copy,path_EXCEL_Save,Sheet_new_name):
''' Function used to copy one EXCEL sheet into another file.
    
    def path_EXCEL_read,Sheet_name_to_copy,path_EXCEL_Save,Sheet_new_name
    
Input data:
    1.) path_EXCEL_read: the location of the EXCEL file along with the name where the information is going to be saved
    2.) Sheet_name_to_copy= The name of the EXCEL sheet to copy
    3.) path_EXCEL_Save: The path of the EXCEL file where the sheet is going to be copied
    3.) Sheet_new_name: The name of the new EXCEL sheet
    
Output data:
    1.) Status= If 0, everything went OK. If 1, one error occurred.

Version History:
1.0 (2017-02-20): Initial version.

'''
status=0

if(path_EXCEL_read.endswith('.xls')==1): 
    print('ERROR - EXCEL xls file format is not supported by openpyxl. Please, convert the file to an XLSX format')
    status=1
    return status
    
try:
   wb = openpyxl.load_workbook(path_EXCEL_read,read_only=True)
except:
    print('ERROR - EXCEL file does not exist in the following location:\n  {0}'.format(path_EXCEL_read))
    status=1
    return status

Sheet_names=wb.get_sheet_names()    # We copare against the sheet name we would like to cpy

if ((Sheet_name_to_copy in Sheet_names)==0):
    print('ERROR - EXCEL sheet does not exist'.format(Sheet_name_to_copy))
    status=1
    return status   

# We checking if the destination file exists

if (os.path.exists(path_EXCEL_Save)==1):
    #If true, file exist so we open it
    
    if(path_EXCEL_Save.endswith('.xls')==1): 
        print('ERROR - Destination EXCEL xls file format is not supported by openpyxl. Please, convert the file to an XLSX format')
        status=1
    return status
    
    try:
        wdestiny = openpyxl.load_workbook(path_EXCEL_Save)
    except:
        print('ERROR - Destination EXCEL file does not exist in the following location:\n  {0}'.format(path_EXCEL_read))
        status=1
    return status

    #we check if the destination sheet exists. If so, we will delete it
    
    destination_list_sheets = wdestiny.get_sheet_names()
    
    if((Sheet_new_name in destination_list_sheets) ==True):
        print('WARNING - Sheet "{0}" exists in: {1}. It will be deleted!'.format(Sheet_new_name,path_EXCEL_Save))
        wdestiny.remove_sheet(Sheet_new_name) 

else:
    wdestiny=openpyxl.Workbook()
# We copy the Excel sheet
    
try:
    sheet_to_copy = wb.get_sheet_by_name(Sheet_name_to_copy) 
    target = wdestiny.copy_worksheet(sheet_to_copy)
    target.title=Sheet_new_name
except:
    print('ERROR - Could not copy the EXCEL sheet. Check the file')
    status=1
    return status

try:
    wdestiny.save(path_EXCEL_Save)
except:
    print('ERROR - Could not save the EXCEL sheet. Check the file permissions')
    status=1
    return status

#Program finishes
return status

I had the same problem. For me style, format, and layout were very important. Moreover, I did not want to copy formulas but only the value (of the formulas). After a lot of trail, error, and stackoverflow I came up with the following functions. It may look a bit intimidating but the code copies a sheet from one Excel file to another (possibly existing file) while preserving:

font and color of text
filled color of cells
merged cells
comment and hyperlinks
format of the cell value
the width of every row and column
whether or not row and column are hidden
frozen rows

It is useful when you want to gather sheets from many workbooks and bind them into one workbook. I copied most attributes but there might be a few more. In that case you can use this script as a jumping off point to add more.

###############
## Copy a sheet with style, format, layout, ect. from one Excel file to another Excel file
## Please add the ..path\\+\\file..  and  ..sheet_name.. according to your desire.

import openpyxl
from copy import copy

def copy_sheet(source_sheet, target_sheet):
    copy_cells(source_sheet, target_sheet)  # copy all the cel values and styles
    copy_sheet_attributes(source_sheet, target_sheet)


def copy_sheet_attributes(source_sheet, target_sheet):
    target_sheet.sheet_format = copy(source_sheet.sheet_format)
    target_sheet.sheet_properties = copy(source_sheet.sheet_properties)
    target_sheet.merged_cells = copy(source_sheet.merged_cells)
    target_sheet.page_margins = copy(source_sheet.page_margins)
    target_sheet.freeze_panes = copy(source_sheet.freeze_panes)

    # set row dimensions
    # So you cannot copy the row_dimensions attribute. Does not work (because of meta data in the attribute I think). So we copy every row's row_dimensions. That seems to work.
    for rn in range(len(source_sheet.row_dimensions)):
        target_sheet.row_dimensions[rn] = copy(source_sheet.row_dimensions[rn])

    if source_sheet.sheet_format.defaultColWidth is None:
        print('Unable to copy default column wide')
    else:
        target_sheet.sheet_format.defaultColWidth = copy(source_sheet.sheet_format.defaultColWidth)

    # set specific column width and hidden property
    # we cannot copy the entire column_dimensions attribute so we copy selected attributes
    for key, value in source_sheet.column_dimensions.items():
        target_sheet.column_dimensions[key].min = copy(source_sheet.column_dimensions[key].min)   # Excel actually groups multiple columns under 1 key. Use the min max attribute to also group the columns in the targetSheet
        target_sheet.column_dimensions[key].max = copy(source_sheet.column_dimensions[key].max)  # https://stackoverflow.com/questions/36417278/openpyxl-can-not-read-consecutive-hidden-columns discussed the issue. Note that this is also the case for the width, not onl;y the hidden property
        target_sheet.column_dimensions[key].width = copy(source_sheet.column_dimensions[key].width) # set width for every column
        target_sheet.column_dimensions[key].hidden = copy(source_sheet.column_dimensions[key].hidden)


def copy_cells(source_sheet, target_sheet):
    for (row, col), source_cell in source_sheet._cells.items():
        target_cell = target_sheet.cell(column=col, row=row)

        target_cell._value = source_cell._value
        target_cell.data_type = source_cell.data_type

        if source_cell.has_style:
            target_cell.font = copy(source_cell.font)
            target_cell.border = copy(source_cell.border)
            target_cell.fill = copy(source_cell.fill)
            target_cell.number_format = copy(source_cell.number_format)
            target_cell.protection = copy(source_cell.protection)
            target_cell.alignment = copy(source_cell.alignment)

        if source_cell.hyperlink:
            target_cell._hyperlink = copy(source_cell.hyperlink)

        if source_cell.comment:
            target_cell.comment = copy(source_cell.comment)


wb_target = openpyxl.Workbook()
target_sheet = wb_target.create_sheet(..sheet_name..)

wb_source = openpyxl.load_workbook(..path\\+\\file_name.., data_only=True)
source_sheet = wb_source[..sheet_name..]

copy_sheet(source_sheet, target_sheet)

if 'Sheet' in wb_target.sheetnames:  # remove default sheet
    wb_target.remove(wb_target['Sheet'])

wb_target.save('out.xlsx')

You cannot use copy_worksheet() to copy between workbooks because it depends on global constants that may vary between workbooks. The only safe and reliable way to proceed is to go row-by-row and cell-by-cell.

You might want to read the discussions about this feature

How to copy worksheet from one workbook to another one using openpyxl?

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