Top n records per group sql in access
I am making some software that tracks the scores of a test. There are multiple users, the details of which are stored in a user table. There is then a progress table which tracks a score with the date and the user who's score it is.
I can already select the 3 most recent records for a chosen userID
SELECT TOP 3 Progress.LoginID, Progress.Score, Progress.[Date Taken]
FROM Progress
WHERE (((Progress.LoginID)=[Enter LoginID:]))
ORDER BY Progress.[Date Taken] DESC;
And I can show all the records grouped by LoginID
SELECT Progress.LoginID, Progress.Score, Progress.[Date Taken]
FROM Progress
GROUP BY Progress.LoginID, Progress.Score, Progress.[Date Taken];
I want to be able to show the 3 most recent records for each user in one query and I'm unsure of how to use nested queries/subqueries to do so.
The field names for the user table are:
LoginID
Forename
Surname
DOB
Guardian Forename
Guardian Surname
Telephone Number
The field names for the progress table are:
ProgressID
LoginID
Score
Date Taken
Any help would be appreciated.
I had a similar problem a year ago: Top 3 per group including 0
Using the same approach, this will return the latest three dates for each LoginID - you may get more than three records if there are tied dates for the same LoginID.
SELECT PR1.LogInID, PR1.Score, PR1.[Date Taken]
FROM Progress AS PR1
WHERE PR1.[Date Taken] IN (
SELECT TOP 3 PR2.[Date Taken]
FROM Progress PR2
WHERE PR2.LoginID = PR1.LoginID
ORDER BY PR2.[Date Taken] DESC
)
ORDER BY LoginID, [Date Taken]