Comparing numbers give the wrong result in Python
Solution 1:
You're testing a string value myAge
against another string value '24'
, as opposed to integer values.
if myAge > ('24'):
print('You are old, ' + myName)
Should be
if int(myAge) > 24:
print('You are old, {}'.format(myName))
In Python, you can greater-than / less-than against strings, but it doesn't work how you might think. So if you want to test the value of the integer representation of the string, use int(the_string)
>>> "2" > "1"
True
>>> "02" > "1"
False
>>> int("02") > int("1")
True
You may have also noticed that I changed print('You are old, ' + myName)
to print('You are old, {}'.format(myName))
-- You should become accustomed to this style of string formatting, as opposed to doing string concatenation with +
-- You can read more about it in the docs. But it really doesn't have anything to do with your core problem.
Solution 2:
The string '100'
is indeed less than the string '24'
, because '1'
is "alphabetically" smaller than '2'
. You need to compare numbers.
my_age = int(input())
if my_age > 24:
Solution 3:
print ('What is your name?')
myName = input ()
print ('Hello, ' + myName)
print ('How old are you?, ' + myName)
myAge = input ()
if int(myAge) > 24:
print('You are old, ' + myName)
else:
print('You will be old before you know it.')
Just a small thing about your code. You should convert the input from myAge
to an integer (int
) (number) and then compare that number to the number 24.;
Also, you should usually not add strings together as it is consider non-pythonic and it slow. Try something like print ('Hello, %s' % myName)
instead of print ('Hello, ' + myName)
.
Python Strings Tutorial