how to show alternate image if source image is not found? (onerror working in IE but not in mozilla) [duplicate]
I think this is very nice and short
<img src="imagenotfound.gif" alt="Image not found" onerror="this.src='imagefound.gif';" />
But, be careful. The user's browser will be stuck in an endless loop if the onerror image itself generates an error.
EDIT
To avoid endless loop, remove the onerror
from it at once.
<img src="imagenotfound.gif" alt="Image not found" onerror="this.onerror=null;this.src='imagefound.gif';" />
By calling this.onerror=null
it will remove the onerror then try to get the alternate image.
NEW I would like to add a jQuery way, if this can help anyone.
<script>
$(document).ready(function()
{
$(".backup_picture").on("error", function(){
$(this).attr('src', './images/nopicture.png');
});
});
</script>
<img class='backup_picture' src='./images/nonexistent_image_file.png' />
You simply need to add class='backup_picture' to any img tag that you want a backup picture to load if it tries to show a bad image.
I have got the solution for my query:
i have done something like this:
cell.innerHTML="<img height=40 width=40 alt='' src='<%=request.getContextPath()%>/writeImage.htm?' onerror='onImgError(this);' onLoad='setDefaultImage(this);'>"
function setDefaultImage(source){
var badImg = new Image();
badImg.src = "video.png";
var cpyImg = new Image();
cpyImg.src = source.src;
if(!cpyImg.width)
{
source.src = badImg.src;
}
}
function onImgError(source){
source.src = "video.png";
source.onerror = "";
return true;
}
This way it's working in all browsers.
If you're open to a PHP solution:
<td><img src='<?PHP
$path1 = "path/to/your/image.jpg";
$path2 = "alternate/path/to/another/image.jpg";
echo file_exists($path1) ? $path1 : $path2;
?>' alt='' />
</td>
////EDIT OK, here's a JS version:
<table><tr>
<td><img src='' id='myImage' /></td>
</tr></table>
<script type='text/javascript'>
document.getElementById('myImage').src = "newImage.png";
document.getElementById('myImage').onload = function() {
alert("done");
}
document.getElementById('myImage').onerror = function() {
alert("Inserting alternate");
document.getElementById('myImage').src = "alternate.png";
}
</script>