File names with spaces in BASH
I'm trying to write script that'll crop and resize large photos into HD Wallpapers.
#! /bin/bash
for i in `ls *.jpg`
do
width=`identify -format '%w' $i`
height=`identify -format '%h' $i`
if [ `echo "$width/$height > 16/9" | bc -l` ]
then
exec `convert $i -resize 1920 -gravity Center -crop '1920x1080+0+0' +repage temp`
else
exec `convert $i -resize x1080 -gravity Center -crop 1920x1080+0+0 +repage temp`
fi
rm $i
mv temp $i
done
But it seems that the script has problems with file names having spaces (like Tumble Weed.jpg). How can I fix this?
Solution 1:
First, you don't need ls
. By using ls
in backtics, you implicitly make bash parse a string into a list, which splits by whitespaces. Instead, make bash generate the list and separate it without such quirks:
Also, you need to enclose all $i
usages into quotes, to make bash substitute it as a whole, not as a string split to separate words.
Here's the script that demonstrates both ideas:
for i in *.jpg ; do
echo "$i";
done
Solution 2:
Use read to circumvent the problem with spaces. It looks a bit unnatural to write the loop like this but it works better:
find . -type f -iname "*.jpg" | while read i
do
# your original code inside the loop using "$i" instead of $i
done
with -iname
you also get the jpg files that might have an extension with different casing like .JPG. "i" in "iname" means ignore casing.
Solution 3:
I would recommend to write the for-line like this:
for i in *.jpg
and encapsulate $i
in double-quotes: "$i"
.
If you insist on the
`ls *.jpg`
style, (if you for instance get your file-names from a more complex command) you could try setting IFS
to \n
:
IFS='\n'
Compare these two executions:
$ for f in `ls *`; do echo $f; done
hello
world
test
$ IFS='\n'; for f in `ls *`; do echo $f; done
hello world
test
Solution 4:
In bash, use string replacement with find
:
${string//substring/replacement}
Replace all matches of$substring
with$replacement
.
so this works:
find . -type f -name '*.jpg' | while read i ; do /bin/mv -f "$i" ${i// /_}; done