How to convert Nonetype to int or string?

python

I've got an Nonetype value x, it's generally a number, but could be None. I want to divide it by a number, but Python raises:

TypeError: int() argument must be a string or a number, not 'NoneType'

How can I solve this?

int(value or 0)

This will use 0 in the case when you provide any value that Python considers False, such as None, 0, [], "", etc. Since 0 is False, you should only use 0 as the alternative value (otherwise you will find your 0s turning into that value).

int(0 if value is None else value)

This replaces only None with 0. Since we are testing for None specifically, you can use some other value as the replacement.

In one of the comments, you say:

Somehow I got an Nonetype value, it supposed to be an int, but it's now a Nonetype object

If it's your code, figure out how you're getting None when you expect a number and stop that from happening.

If it's someone else's code, find out the conditions under which it gives None and determine a sensible value to use for that, with the usual conditional code:

result = could_return_none(x)

if result is None:
    result = DEFAULT_VALUE

...or even...

if x == THING_THAT_RESULTS_IN_NONE:
    result = DEFAULT_VALUE
else:
    result = could_return_none(x) # But it won't return None, because we've restricted the domain.

There's no reason to automatically use 0 here — solutions that depend on the "false"-ness of None assume you will want this. The DEFAULT_VALUE (if it even exists) completely depends on your code's purpose.

A common "Pythonic" way to handle this kind of situation is known as EAFP for "It's easier to ask forgiveness than permission". Which usually means writing code that assumes everything is fine, but then wrapping it with a try...except block to handle things—just in case—it's not.

Here's that coding style applied to your problem:

try:
    my_value = int(my_value)
except TypeError:
    my_value = 0  # or whatever you want to do

answer = my_value / divisor

Or perhaps the even simpler and slightly faster:

try:
    answer = int(my_value) / divisor
except TypeError:
    answer = 0

The inverse and more traditional approach is known as LBYL which stands for "Look before you leap" is what @Soviut and some of the others have suggested. For additional coverage of this topic see my answer and associated comments to the question Determine whether a key is present in a dictionary elsewhere on this site.

One potential problem with EAFP is that it can hide the fact that something is wrong with some other part of your code or third-party module you're using, especially when the exceptions frequently occur (and therefore aren't really "exceptional" cases at all).

That TypeError only appears when you try to pass int() None (which is the only NoneType value, as far as I know). I would say that your real goal should not be to convert NoneType to int or str, but to figure out where/why you're getting None instead of a number as expected, and either fix it or handle the None properly.

How to convert Nonetype to int or string?

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