How to round up value C# to the nearest integer?

Use Math.Ceiling to round up

Math.Ceiling(0.5); // 1

Use Math.Round to just round

Math.Round(0.5, MidpointRounding.AwayFromZero); // 1

And Math.Floor to round down

Math.Floor(0.5); // 0

Check out Math.Round. You can then cast the result to an int.

The .NET framework uses banker's rounding in Math.Round by default. You should use this overload:

Math.Round(0.5d, MidpointRounding.AwayFromZero)  //1
Math.Round(0.4d, MidpointRounding.AwayFromZero)  //0

Math.Round

Rounds a double-precision floating-point value to the nearest integral value.

Use a function in place of MidpointRounding.AwayFromZero:

myRound(1.11125,4)

Answer:- 1.1114

public static Double myRound(Double Value, int places = 1000)
{
    Double myvalue = (Double)Value;
    if (places == 1000)
    {
        if (myvalue - (int)myvalue == 0.5)
        {
            myvalue = myvalue + 0.1;
            return (Double)Math.Round(myvalue);
        }
        return (Double)Math.Round(myvalue);
        places = myvalue.ToString().Substring(myvalue.ToString().IndexOf(".") + 1).Length - 1;
    } if ((myvalue * Math.Pow(10, places)) - (int)(myvalue * Math.Pow(10, places)) > 0.49)
    {
        myvalue = (myvalue * Math.Pow(10, places + 1)) + 1;
        myvalue = (myvalue / Math.Pow(10, places + 1));
    }
    return (Double)Math.Round(myvalue, places);
}