How should I pass an int into stringWithFormat?

Do this:

label.text = [NSString stringWithFormat:@"%d", count];

Keep in mind that @"%d" will only work on 32 bit. Once you start using NSInteger for compatibility if you ever compile for a 64 bit platform, you should use @"%ld" as your format specifier.

Marc Charbonneau wrote:

Keep in mind that @"%d" will only work on 32 bit. Once you start using NSInteger for compatibility if you ever compile for a 64 bit platform, you should use @"%ld" as your format specifier.

Interesting, thanks for the tip, I was using @"%d" with my NSIntegers!

The SDK documentation also recommends to cast NSInteger to long in this case (to match the @"%ld"), e.g.:

NSInteger i = 42;
label.text = [NSString stringWithFormat:@"%ld", (long)i];

Source: String Programming Guide for Cocoa - String Format Specifiers (Requires iPhone developer registration)

You want to use %d or %i for integers. %@ is used for objects.

It's worth noting, though, that the following code will accomplish the same task and is much clearer.

label.intValue = count;

And for comedic value:

label.text = [NSString stringWithFormat:@"%@", [NSNumber numberWithInt:count]];

(Though it could be useful if one day you're dealing with NSNumber's)