How to get element by innerText
Solution 1:
You could use xpath to accomplish this
var xpath = "//a[text()='SearchingText']";
var matchingElement = document.evaluate(xpath, document, null, XPathResult.FIRST_ORDERED_NODE_TYPE, null).singleNodeValue;
You can also search of an element containing some text using this xpath:
var xpath = "//a[contains(text(),'Searching')]";
Solution 2:
You'll have to traverse by hand.
var aTags = document.getElementsByTagName("a");
var searchText = "SearchingText";
var found;
for (var i = 0; i < aTags.length; i++) {
if (aTags[i].textContent == searchText) {
found = aTags[i];
break;
}
}
// Use `found`.
Solution 3:
Using the most modern syntax available at the moment, it can be done very cleanly like this:
for (const a of document.querySelectorAll("a")) {
if (a.textContent.includes("your search term")) {
console.log(a.textContent)
}
}
Or with a separate filter:
[...document.querySelectorAll("a")]
.filter(a => a.textContent.includes("your search term"))
.forEach(a => console.log(a.textContent))
Naturally, legacy browsers won't handle this, but you can use a transpiler if legacy support is needed.
Solution 4:
You can use jQuery :contains() Selector
var element = $( "a:contains('SearchingText')" );
Solution 5:
function findByTextContent(needle, haystack, precise) {
// needle: String, the string to be found within the elements.
// haystack: String, a selector to be passed to document.querySelectorAll(),
// NodeList, Array - to be iterated over within the function:
// precise: Boolean, true - searches for that precise string, surrounded by
// word-breaks,
// false - searches for the string occurring anywhere
var elems;
// no haystack we quit here, to avoid having to search
// the entire document:
if (!haystack) {
return false;
}
// if haystack is a string, we pass it to document.querySelectorAll(),
// and turn the results into an Array:
else if ('string' == typeof haystack) {
elems = [].slice.call(document.querySelectorAll(haystack), 0);
}
// if haystack has a length property, we convert it to an Array
// (if it's already an array, this is pointless, but not harmful):
else if (haystack.length) {
elems = [].slice.call(haystack, 0);
}
// work out whether we're looking at innerText (IE), or textContent
// (in most other browsers)
var textProp = 'textContent' in document ? 'textContent' : 'innerText',
// creating a regex depending on whether we want a precise match, or not:
reg = precise === true ? new RegExp('\\b' + needle + '\\b') : new RegExp(needle),
// iterating over the elems array:
found = elems.filter(function(el) {
// returning the elements in which the text is, or includes,
// the needle to be found:
return reg.test(el[textProp]);
});
return found.length ? found : false;;
}
findByTextContent('link', document.querySelectorAll('li'), false).forEach(function(elem) {
elem.style.fontSize = '2em';
});
findByTextContent('link3', 'a').forEach(function(elem) {
elem.style.color = '#f90';
});
<ul>
<li><a href="#">link1</a>
</li>
<li><a href="#">link2</a>
</li>
<li><a href="#">link3</a>
</li>
<li><a href="#">link4</a>
</li>
<li><a href="#">link5</a>
</li>
</ul>
Of course, a somewhat simpler way still is:
var textProp = 'textContent' in document ? 'textContent' : 'innerText';
// directly converting the found 'a' elements into an Array,
// then iterating over that array with Array.prototype.forEach():
[].slice.call(document.querySelectorAll('a'), 0).forEach(function(aEl) {
// if the text of the aEl Node contains the text 'link1':
if (aEl[textProp].indexOf('link1') > -1) {
// we update its style:
aEl.style.fontSize = '2em';
aEl.style.color = '#f90';
}
});
<ul>
<li><a href="#">link1</a>
</li>
<li><a href="#">link2</a>
</li>
<li><a href="#">link3</a>
</li>
<li><a href="#">link4</a>
</li>
<li><a href="#">link5</a>
</li>
</ul>
References:
-
Array.prototype.filter()
. -
Array.prototype.forEach()
. -
Array.prototype.slice()
. -
Conditional ('ternary',
assessment ? ifTrue : ifFalse
) operator. -
Function.prototype.call()
. -
typeof
operator.