For loop of two variables in Go
Solution 1:
You don't have a comma operator to join multiple statements, but you do have multiple assignment, so this works:
package main
import (
"fmt"
)
func main() {
for i, j := 0, 1; i < 10; i, j = i+1, j+1 {
fmt.Println("Hello, playground")
}
}
Solution 2:
Although above Answer is accepted, and it fully satisfy the need. But I would like to contribute some further explanation to it.
Golang Does not support many things which could be done in simple terms. For loop is a most common example of this. The beauty of Go's For loop is that it merges many modern style of looping into one keyword.
Similarly Golang do with Multiple Variable declaration and assignment. According to above mentioned problem, We could solve multi-variable for loop with this simple tool which Golang provides us. If you want to look into further explanation, this question provide further details and way of declaring multiple variables in one statement.
Coming back to for loop, If we want to declare variable of same datatype we can declare them with this
var a,b,c string
but we use short hand in for loop so we can do this for initializing them with same value
i,j := 0,1
Different Datatypes and Different Values
and if we want to declare different type of variables and want to assign different values we can do this by separating variables names and after := different values by comma as well. for example
c,i,f,b := 'c',23423,21.3,false
Usage of Assignment Operator
Later on, we can assign values to multiple variables with the same approach.
x,y := 10.3, 2
x,y = x+10, y+1
Mixing Struct and Normal types in single statement
Even we can use struct types or pointers the same way. Here is a function to iterate Linked list which is defined as a struct
func (this *MyLinkedList) Get(index int) int {
for i,list := 0,this; list != nil; i,list = i+1,list.Next{
if(i==index){
return list.Val
}
}
return -1
}
This list is defined as
type MyLinkedList struct {
Val int
Next *MyLinkedList
}
Answering to Original Problem
Coming to the origin Question, Simply it could be done
for i, j := 0, 1; i < 10; i, j = i+1, j+1 {
fmt.Println("i,j",i,j)
}