Angular 2 TypeScript how to find element in Array
I have a Component and a Service:
Component:
export class WebUserProfileViewComponent {
persons: Person [];
personId: number;
constructor( params: RouteParams, private personService: PersonService) {
this.personId = params.get('id');
this.persons = this. personService.getPersons();
console.log(this.personId);
}
}
Service:
@Injectable()
export class PersonService {
getPersons(){
var persons: Person[] = [
{id: 1, firstName:'Hans', lastName:'Mustermann', email: '[email protected]', company:'Test', country:'DE'},
{id: 2, firstName:'Muster', lastName:'Mustermann', email: '[email protected]', company:'test', country:'DE'},
{id:3, firstName:'Thomas', lastName:'Mustermann', email: '[email protected]', company:'test', country:'DE'}
];
return persons;
}
}
I want to get the Person Item with the Id ('personID'). The personID i get from Routeparam. For that I need the foreach loop? But I haven´t found a solution for this.
Solution 1:
You need to use method Array.filter
:
this.persons = this.personService.getPersons().filter(x => x.id == this.personId)[0];
or Array.find
this.persons = this.personService.getPersons().find(x => x.id == this.personId);
Solution 2:
Assume I have below array:
Skins[
{Id: 1, Name: "oily skin"},
{Id: 2, Name: "dry skin"}
];
If we want to get item with Id = 1
and Name = "oily skin"
, We'll try as below:
var skinName = skins.find(x=>x.Id == "1").Name;
The result will return the skinName is "Oily skin".
Solution 3:
You could combine .find
with arrow functions and destructuring. Take this example from MDN.
const inventory = [
{name: 'apples', quantity: 2},
{name: 'bananas', quantity: 0},
{name: 'cherries', quantity: 5}
];
const result = inventory.find( ({ name }) => name === 'cherries' );
console.log(result) // { name: 'cherries', quantity: 5 }