This is straight from PEP 484 -- Type Hints documentation:

When used in a type hint, the expression None is considered equivalent to type(None).

And, as you can see most of the examples use None as return type.


TLDR: The idiomatic equivalent of a void return type annotation is -> None.

def foo() -> None:
    ...

This matches that a function without return or just a bare return evaluates to None.

def void_func():  # unannotated void function
    pass

print(void_func())  # None

Omitting the return type does not mean that there is no return value. As per PEP 484:

For a checked function, the default annotation for arguments and for the return type is Any.

This means the value is considered dynamically typed and statically supports any operation. That is practically the opposite meaning of void.


Type-hinting in Python does not strictly require actual types. For example, annotations may use strings of type names: Union[str, int], Union[str, 'int'], 'Union[str, int]' and various variants are equivalent.

Similarly, the type annotation None is considered to mean "is of NoneType". This can be used in other situations as well as return types, though you will see it most often as a return-type annotation:

bar : None

def foo(baz: None) -> None:
    return None

This also applies to generic types. For example, you can use None in Generator[int, None, None] to indicate a generator does not take or return values.


Even though PEP 484 suggests that None means type(None), you should not use the latter form explicitly. The type-hinting specification does not include any form of type(...). This is technically a runtime expression, and its support is entirely up to the type checker. The mypy project is considering whether to remove support for type(None) and remove it from 484 as well.

Or maybe we should update PEP 484 to not suggest that type(None) is valid as a type, and None is the only correct spelling? There should one -- and preferably only one -- obvious way to do it etc.

--- JukkaL, 18 May 2018