GetProperties() to return all properties for an interface inheritance hierarchy
Assuming the following hypothetical inheritance hierarchy:
public interface IA
{
int ID { get; set; }
}
public interface IB : IA
{
string Name { get; set; }
}
Using reflection and making the following call:
typeof(IB).GetProperties(BindingFlags.Public | BindingFlags.Instance)
will only yield the properties of interface IB
, which is "Name
".
If we were to do a similar test on the following code,
public abstract class A
{
public int ID { get; set; }
}
public class B : A
{
public string Name { get; set; }
}
the call typeof(B).GetProperties(BindingFlags.Public | BindingFlags.Instance)
will return an array of PropertyInfo
objects for "ID
" and "Name
".
Is there an easy way to find all the properties in the inheritance hierarchy for interfaces as in the first example?
Solution 1:
I've tweaked @Marc Gravel's example code into a useful extension method encapsulates both classes and interfaces. It also add's the interface properties first which I believe is the expected behaviour.
public static PropertyInfo[] GetPublicProperties(this Type type)
{
if (type.IsInterface)
{
var propertyInfos = new List<PropertyInfo>();
var considered = new List<Type>();
var queue = new Queue<Type>();
considered.Add(type);
queue.Enqueue(type);
while (queue.Count > 0)
{
var subType = queue.Dequeue();
foreach (var subInterface in subType.GetInterfaces())
{
if (considered.Contains(subInterface)) continue;
considered.Add(subInterface);
queue.Enqueue(subInterface);
}
var typeProperties = subType.GetProperties(
BindingFlags.FlattenHierarchy
| BindingFlags.Public
| BindingFlags.Instance);
var newPropertyInfos = typeProperties
.Where(x => !propertyInfos.Contains(x));
propertyInfos.InsertRange(0, newPropertyInfos);
}
return propertyInfos.ToArray();
}
return type.GetProperties(BindingFlags.FlattenHierarchy
| BindingFlags.Public | BindingFlags.Instance);
}
Solution 2:
Type.GetInterfaces
returns the flattened hierarchy, so there is no need for a recursive descent.
The entire method can be written much more concisely using LINQ:
public static IEnumerable<PropertyInfo> GetPublicProperties(this Type type)
{
if (!type.IsInterface)
return type.GetProperties();
return (new Type[] { type })
.Concat(type.GetInterfaces())
.SelectMany(i => i.GetProperties());
}
Solution 3:
Interface hierarchies are a pain - they don't really "inherit" as such, since you can have multiple "parents" (for want of a better term).
"Flattening" (again, not quite the right term) the hierarchy might involve checking for all the interfaces that the interface implements and working from there...
interface ILow { void Low();}
interface IFoo : ILow { void Foo();}
interface IBar { void Bar();}
interface ITest : IFoo, IBar { void Test();}
static class Program
{
static void Main()
{
List<Type> considered = new List<Type>();
Queue<Type> queue = new Queue<Type>();
considered.Add(typeof(ITest));
queue.Enqueue(typeof(ITest));
while (queue.Count > 0)
{
Type type = queue.Dequeue();
Console.WriteLine("Considering " + type.Name);
foreach (Type tmp in type.GetInterfaces())
{
if (!considered.Contains(tmp))
{
considered.Add(tmp);
queue.Enqueue(tmp);
}
}
foreach (var member in type.GetMembers())
{
Console.WriteLine(member.Name);
}
}
}
}
Solution 4:
Exactly the same problem has a workaround described here.
FlattenHierarchy doesnt work btw. (only on static vars. says so in intellisense)
Workaround. Beware of duplicates.
PropertyInfo[] pis = typeof(IB).GetProperties(BindingFlags.Public | BindingFlags.Instance);
Type[] tt = typeof(IB).GetInterfaces();
PropertyInfo[] pis2 = tt[0].GetProperties(BindingFlags.Public | BindingFlags.Instance);