Does new[] call default constructor in C++?
See the accepted answer to a very similar question. When you use new[] each element is initialized by the default constructor except when the type is a built-in type. Built-in types are left unitialized by default.
To have built-in type array default-initialized use
new int[size]();
Built-in types don't have a default constructor even though they can in some cases receive a default value.
But in your case, new just allocates enough space in memory to store count int objects, ie. it allocates sizeof<int>*count.