How to get list of arguments?

I'd like to find a Windows batch counterpart to Bash's $@ that holds a list of all arguments passed into a script.

Or I have to bother with shift?

Solution 1:

dancavallaro has it right, %* for all command line parameters (excluding the script name itself). You might also find these useful:

%0 - the command used to call the batch file (could be foo, ..\foo, c:\bats\foo.bat, etc.)
%1 is the first command line parameter,
%2 is the second command line parameter,
and so on till %9 (and SHIFT can be used for those after the 9th).

%~nx0 - the actual name of the batch file, regardless of calling method (some-batch.bat)
%~dp0 - drive and path to the script (d:\scripts)
%~dpnx0 - is the fully qualified path name of the script (d:\scripts\some-batch.bat)

More info examples at https://www.ss64.com/nt/syntax-args.html and https://www.robvanderwoude.com/parameters.html

Solution 2:

%* seems to hold all of the arguments passed to the script.