What method in the String class returns only the first N characters?

I'd like to write an extension method to the String class so that if the input string to is longer than the provided length N, only the first N characters are to be displayed.

Here's how it looks like:

public static string TruncateLongString(this string str, int maxLength)
{
    if (str.Length <= maxLength)
        return str;
    else
        //return the first maxLength characters                
}

What String.*() method can I use to get only the first N characters of str?

Solution 1:

public static string TruncateLongString(this string str, int maxLength)
{
    if (string.IsNullOrEmpty(str)) return str;

    return str.Substring(0, Math.Min(str.Length, maxLength));
}

In C# 8 or later it is also possible to use a Range to make this a bit terser:

public static string TruncateLongString(this string str, int maxLength)
{
    return str?[0..Math.Min(str.Length, maxLength)];
}

Which can be further reduced using an expression body:

public static string TruncateLongString(this string str, int maxLength) =>
    str?[0..Math.Min(str.Length, maxLength)];

Note null-conditional operator (?) is there to handle the case where str is null. This replaces the need for an explict null check.

Solution 2:

string truncatedToNLength = new string(s.Take(n).ToArray());  

This solution has a tiny bonus in that if n is greater than s.Length, it still does the right thing.

Solution 3:

You can use LINQ str.Take(n) or str.SubString(0, n), where the latter will throw an ArgumentOutOfRangeException exception for n > str.Length.

Mind that the LINQ version returns a IEnumerable<char>, so you'd have to convert the IEnumerable<char> to string: new string(s.Take(n).ToArray()).