Promise.all behavior with RxJS Observables?

Solution 1:

The more straightforward alternative for emulating Promise.all is to use the forkJoin operator (it starts all observables in parallel and join their last elements):

• documentation
• related link: Cf. RxJS: concat three promises, distinguish results

A bit out of scope, but in case it helps, on the subject of chaining promises, you can use a simple flatMap : Cf. RxJS Promise Composition (passing data)

Solution 2:

Update May 2019 using RxJs v6

Found the other answers useful, and wished to offer an example for the answer offered by Arnaud about zip usage.

Here is a snippet showing the equivalence between Promise.all and the rxjs zip (note also, in rxjs6 how zip now gets imported using "rxjs" & not as an operator).

import { zip } from "rxjs";

const the_weather = new Promise(resolve => {
  setTimeout(() => {
    resolve({ temp: 29, conditions: "Sunny with Clouds" });
  }, 2000);
});

const the_tweets = new Promise(resolve => {
  setTimeout(() => {
    resolve(["I like cake", "BBQ is good too!"]);
  }, 500);
});

// Using RxJs
let source$ = zip(the_weather, the_tweets);
source$.subscribe(([weatherInfo, tweetInfo]) =>
  console.log(weatherInfo, tweetInfo)
);

// Using ES6 Promises
Promise.all([the_weather, the_tweets]).then(responses => {
  const [weatherInfo, tweetInfo] = responses;
  console.log(weatherInfo, tweetInfo);
});

The output from both are the same. Running the above gives:

{ temp: 29, conditions: 'Sunny with Clouds' } [ 'I like cake', 'BBQ is good too!' ]
{ temp: 29, conditions: 'Sunny with Clouds' } [ 'I like cake', 'BBQ is good too!' ]

Solution 3:

forkJoin works fine too, but I'd prefer combineLatest since you don't need to worry about it taking the last value of observables. This way, you can just get updated whenever any of them emit a new value too (e.g. you fetch on an interval or something).