gensim word2vec: Find number of words in vocabulary

After training a word2vec model using python gensim, how do you find the number of words in the model's vocabulary?

Solution 1:

In recent versions, the model.wv property holds the words-and-vectors, and can itself can report a length – the number of words it contains. So if w2v_model is your Word2Vec (or Doc2Vec or FastText) model, it's enough to just do:

vocab_len = len(w2v_model.wv)

If your model is just a raw set of word-vectors, like a KeyedVectors instance rather than a full Word2Vec/etc model, it's just:

vocab_len = len(kv_model)

Other useful internals in Gensim 4.0+ include model.wv.index_to_key, a plain list of the key (word) in each index position, and model.wv.key_to_index, a plain dict mapping keys (words) to their index positions.

In pre-4.0 versions, the vocabulary was in the vocab field of the Word2Vec model's wv property, as a dictionary, with the keys being each token (word). So there it was just the usual Python for getting a dictionary's length:

len(w2v_model.wv.vocab)

In very-old gensim versions before 0.13 vocab appeared directly on the model. So way back then you would use w2v_model.vocab instead of w2v_model.wv.vocab.

But if you're still using anything from before Gensim 4.0, you should definitely upgrade! There are big memory & performance improvements, and the changes required in calling code are relatively small – some renamings & moves, covered in the 4.0 Migration Notes.

Solution 2:

One more way to get the vocabulary size is from the embedding matrix itself as in:

In [33]: from gensim.models import Word2Vec

# load the pretrained model
In [34]: model = Word2Vec.load(pretrained_model)

# get the shape of embedding matrix    
In [35]: model.wv.vectors.shape
Out[35]: (662109, 300)

# `vocabulary_size` is just the number of rows (i.e. axis 0)
In [36]: model.wv.vectors.shape[0]
Out[36]: 662109

Solution 3:

Gojomo's answer raises an AttributeError for Gensim 4.0.0+.

For these versions, you can get the length of the vocabulary as follows:

len(w2v_model.wv.index_to_key)

(which is slightly faster than: len(w2v_model.wv.key_to_index))