How to make <div> fill <td> height
Solution 1:
If you give your TD a height of 1px, then the child div would have a heighted parent to calculate it's % from. Because your contents would be larger then 1px, the td would automatically grow, as would the div. Kinda a garbage hack, but I bet it would work.
Solution 2:
CSS height: 100% only works if the element's parent has an explicitly defined height. For example, this would work as expected:
td {
height: 200px;
}
td div {
/* div will now take up full 200px of parent's height */
height: 100%;
}
Since it seems like your <td>
is going to be variable height, what if you added the bottom right icon with an absolutely positioned image like so:
.thatSetsABackgroundWithAnIcon {
/* Makes the <div> a coordinate map for the icon */
position: relative;
/* Takes the full height of its parent <td>. For this to work, the <td>
must have an explicit height set. */
height: 100%;
}
.thatSetsABackgroundWithAnIcon .theIcon {
position: absolute;
bottom: 0;
right: 0;
}
With the table cell markup like so:
<td class="thatSetsABackground">
<div class="thatSetsABackgroundWithAnIcon">
<dl>
<dt>yada
</dt>
<dd>yada
</dd>
</dl>
<img class="theIcon" src="foo-icon.png" alt="foo!"/>
</div>
</td>
Edit: using jQuery to set div's height
If you keep the <div>
as a child of the <td>
, this snippet of jQuery will properly set its height:
// Loop through all the div.thatSetsABackgroundWithAnIcon on your page
$('div.thatSetsABackgroundWithAnIcon').each(function(){
var $div = $(this);
// Set the div's height to its parent td's height
$div.height($div.closest('td').height());
});
Solution 3:
You could try making your div float:
.thatSetsABackgroundWithAnIcon{
float:left;
}
Alternativelly, use inline-block:
.thatSetsABackgroundWithAnIcon{
display:inline-block;
}
Working example of the inline-block method:
table,
th,
td {
border: 1px solid black;
}
<table>
<tr>
<td>
<div style="border:1px solid red; height:100%; display:inline-block;">
I want cell to be the full height
</div>
</td>
<td>
This cell
<br/>is higher
<br/>than the
<br/>first one
</td>
</tr>
</table>